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#238 ll Show that (∃x)[ P(x) ∧ Q(x) ]⇒(∃x)P(x) ∧ (∃x)Q(x) ll Discrete Mathematics

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#238 ll Show that (∃x)[ P(x) ∧ Q(x) ]⇒(∃x)P(x) ∧ (∃x)Q(x) ll Discrete Mathematics

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